Why does call-by-value example not modify input parameter?

Question

In the following call-by-value example, I cannot understand why this code is not changing the value of the 5 to a 6.

Line 11 calls the function changeValue which ha

Answer 1

AND:

the copy is assigned 6, but the change is not returned.

you need some reference or pointer if you want to change the value:

try using a method signature like:

void changeValue(int& value)

that will probably do what you expected