I tried this code:
class A
{
virtual void foo() = 0;
};
class B
{
virtual void foo() = 0;
};
class C : public A, public B
{
//virtual void A::f
You can resolve this ambiguity with different function parameters.
In real-world code, such virtual functions do something, so they usually already have either:
(In my own code I usually find myself in case (1), sometimes in (2), never so far in (3).)
Your example is case (3) and would look like this:
class A
{
public:
struct tag_a { };
virtual void foo(tag_a) = 0;
};
class B
{
public:
struct tag_b { };
virtual void foo(tag_b) = 0;
};
class C : public A, public B
{
void foo(tag_a) override;
void foo(tag_b) override;
};