Count days between two dates, excluding weekends (MySQL only)

Question

I need to calculate the difference (in days) between two dates in MySQL excluding weekends (Saturday and Sunday). That is, the difference in days minus the number of Saturda

Answer 1

IT my helpful to you

The bellow logic only show the how many days like

sun   mon

1      2 .....................

DELIMITER $$
DROP FUNCTION IF EXISTS `xx`.`get_weekday` $$
CREATE FUNCTION `xx`.`get_weekday` (first_date date, last_date date, curr_week_day int) RETURNS INT
BEGIN
DECLARE days_tot int;
DECLARE whole_weeks int;
DECLARE first_day int;
DECLARE last_day int;
SET whole_weeks = FLOOR(DATEDIFF(last_date,first_date)/7) ;
SET first_day = WEEKDAY(first_date) ;
SET last_day = WEEKDAY(last_date)  ;
IF curr_week_day  BETWEEN first_day AND  last_day
           AND  last_day > first_day
           OR ( curr_week_day BETWEEN last_day AND first_day
           AND  last_day <  first_day  )
THEN SET days_tot = whole_weeks + 1;
ELSE SET days_tot = whole_weeks ;
END IF;
RETURN  days_tot;
END $$
DELIMITER ;

    SELECT
      `xx`.`get_weekday` ('2009-01-01', '2009-07-20', 0) as mo,
      `xx`.`get_weekday` ('2009-01-01', '2009-07-20', 1) as tu,
      `xx`.`get_weekday` ('2009-01-01', '2009-07-20', 2) as we,
      `xx`.`get_weekday` ('2009-01-01', '2009-07-20', 3) as th,
      `xx`.`get_weekday` ('2009-01-01', '2009-07-20', 4) as fr,
      `xx`.`get_weekday` ('2009-01-01', '2009-07-20', 5) as sa,
      `xx`.`get_weekday` ('2009-01-01', '2009-07-20', 6) as su;

Table based query

ip:

Weekday count
2        10
3         5


SELECT WEEKDAY( `req_date_time` ) AS weekday, COUNT( id ) AS id
FROM `ffffd`
WHERE (
`req_date_time` >= '2014-12-01'
AND `req_date_time` <= '2014-12-31'
)
AND WEEKDAY( `req_date_time` ) != '1'
GROUP BY WEEKDAY( `req_date_time` )