Is there a default type for numbers in Java

Question

If I write something like this

System.out.println(18);

Which type has the \'18\'? Is it int or byte? Or doesn\'t it have

Answer 1

The JLS-4.2.1 - Integral Types and Values

The values of the integral types are integers in the following ranges:

• For byte, from -128 to 127, inclusive
• For short, from -32768 to 32767, inclusive
• For int, from -2147483648 to 2147483647, inclusive
• For long, from -9223372036854775808 to 9223372036854775807, inclusive
• For char, from '\u0000' to '\uffff' inclusive, that is, from 0 to 65535

And JLS-3.10.1 - Integer Literals

An integer literal is of type long if it is suffixed with an ASCII letter L or l (ell); otherwise it is of type int (§4.2.1).

Finally, JLS-3.10.2 - Floating-Point Literals includes

A floating-point literal is of type float if it is suffixed with an ASCII letter F or f; otherwise its type is double and it can optionally be suffixed with an ASCII letter D or d (§4.2.3).

As for byte b = 3; it is a Narrowing Conversion from int to byte.