Python Loop: List Index Out of Range

Question

Given the following list

a = [0, 1, 2, 3]

I\'d like to create a new list b, which consists of elements for which the current a

Answer 1

When you call for i in a:, you are getting the actual elements, not the indexes. When we reach the last element, that is 3, b.append(a[i+1]-a[i]) looks for a[4], doesn't find one and then fails. Instead, try iterating over the indexes while stopping just short of the last one, like

for i in range(0, len(a)-1): Do something

Your current code won't work yet for the do something part though ;)