Firestore get documents where value not in array?

Question

Is there a way to get all documents which array field does not contain one or more values, now there is \"array-contains\" but is there something like \"array-not-contains\"

Answer 1

Firestore recently added support for a not-in clause.

citiesRef.where('country', 'not-in', ['USA', 'Japan']);

That will get every doc where country exists and has a value other than 'USA', 'Japan', or 'null'.