C++/C function pointers that return void*

Question

I\'m trying to call a function that takes an argument, void(*)(void*, int, const char*), but I cannot figure out how to pass those arguments to the function.

Answer 1

The usual trick is to use a typedef for signature:

 typedef void signature_t (void*, int, const char*);

^{Notice that without the typedef the syntax is like a function declaration. It declares signature_t as a typedef for functions, so you'll always use pointers to signature_t in practice.}

Then you can declare your "high-order" function as

 int function (int, int, signature_t*);

See also this reply.