A simple for loop should do it:
def check(lst):
last = lst[0]
for num in lst[1:]:
if num == last:
return True
last = num
return False
lst = [1, 2, 3, 4, 5, 5, 6]
print (check(lst)) #Prints True
Here, in each loop, I check if the current element is equal to the previous element.