Passing two-dimensional array via pointer

Question

How do I pass the m matrix to foo()? if I am not allowed to change the code or the prototype of foo()?

void foo(float **pm)
{
    int i,j;
    for (i = 0; i          


        

Answer 1

void foo(float **pm) is the same as void foo(float *pm[]) which is not a two-dimensional array of floats. It is an array of float*. Now, those float* may themselves point to float arrays, but that's a separate matter.