Calling a const function rather than its non-const version

Question

I tried to wrap something similar to Qt\'s shared data pointers for my purposes, and upon testing I found out that when the const function should be called, its non-const ve

Answer 1

But testType is not a const object.

Thus it will call the non const version of its members.
If the methods have exactly the same parameters it has to make a choice on which version to call (so it uses the this parameter (the hidden one)). In this case this is not const so you get the non-const method.

testType const test2;
test2->x();  // This will call the const version

This does not affect the call to x() as you can call a const method on a non const object.