Calling a const function rather than its non-const version

Question

I tried to wrap something similar to Qt\'s shared data pointers for my purposes, and upon testing I found out that when the const function should be called, its non-const ve

Answer 1

It doesn't matter whether Data::x is a constant function or not. The operator being called belongs to container class and not Data class, and its instance is not constant, so non-constant operator is called. If there was only constant operator available or the instance of the class was constant itself, then constant operator would have been called.