I've been using Hamid's answer for a while, but it in cases where the languages array is like ["en", "en-GB", "en-US", "fr-FR", "fr", "en-ZA"] it will return "en", when "en-GB" would be a better match.
My update (below) will return the first long format code e.g. "en-GB", otherwise it will return the first short code e.g. "en", otherwise it will return null.
function getFirstBrowserLanguage() {
var nav = window.navigator,
browserLanguagePropertyKeys = ['language', 'browserLanguage', 'systemLanguage', 'userLanguage'],
i,
language,
len,
shortLanguage = null;
// support for HTML 5.1 "navigator.languages"
if (Array.isArray(nav.languages)) {
for (i = 0; i < nav.languages.length; i++) {
language = nav.languages[i];
len = language.length;
if (!shortLanguage && len) {
shortLanguage = language;
}
if (language && len>2) {
return language;
}
}
}
// support for other well known properties in browsers
for (i = 0; i < browserLanguagePropertyKeys.length; i++) {
language = nav[browserLanguagePropertyKeys[i]];
//skip this loop iteration if property is null/undefined. IE11 fix.
if (language == null) { continue; }
len = language.length;
if (!shortLanguage && len) {
shortLanguage = language;
}
if (language && len > 2) {
return language;
}
}
return shortLanguage;
}
console.log(getFirstBrowserLanguage());
Update: IE11 was erroring when some properties were undefined. Added a check to skip those properties.