Why does scanf() need & operator (address-of) in some cases, and not others?

Question

Why do we need to put a & operator in scanf() for storing values in an integer array but not while storing a string in a char array?

Answer 1

• All the variables used to recieve values through scanf() must be passed by their addresses. This means that all arguments must be pointed to the variables used as arguments.

  scanf("%d", &count);

• Stings are read into character arrays, and the array name without any index is the address of the first element of the array.So to read a string into a character array address, we use

  scanf("%s",address);

• In this case address is already a pointer and need not to be preceded by the & operator.