Check if an item is in a nested list

Question

in a simple list following check is trivial:

x = [1, 2, 3]

2 in x  -> True

but if it is a list of list, such as:

x = [[         


        

Answer 1

My code is based on Óscar López's solution. His solution wasn't exactly what I needed for my problem but it gave enough info for me to figure out my problem. So if you have nested elements in one list and need to see if they're in another nested list, this would work.

#!python2

lst1 = [['a', '1'], ['b', '2'], ['c', '3'], ['d', '4'], ['e', '5']]
lst2 = [['b', '2'], ['d', '4'], ['f', '6'], ['h', '8'], ['j', '10'], ['l', '12'], ['n', '14']]

# comparing by index 0, prints lst1 items that aren't in lst2
for i in lst1:
    if not any(i[0] in sublst for sublst in lst2):
        print i
'''
['a', '1']
['c', '3']
['e', '5']
'''

print

# comparing by index 0, prints lst2 items that aren't in lst1
for i in lst2:
    if not any(i[0] in sublst for sublst in lst1):
        print i
'''
['f', '6']
['h', '8']
['j', '10']
['l', '12']
['n', '14']
'''