How does signal assignment work in a process?

Question

I learned that a signal is not changed immediately when encountering an expression, but when the process ends. In this example here:

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signal x,y,z : bit;
         


        

Answer 1

The way it works:

Y changes and the process begins.

X will be assigned to what Y's value currently is, but not until the end of the process

Z will be assigned to not X's old value but not until the end of the process

The process ends so now X and Z will be updated