How to return an Ajax result using async/await?

Question

Trying to get familiar with async/await, I\'ve tried the following code in Chrome:

async function f() { 
     return await $.get(\'/\');
};
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Answer 1

await and async are basically just syntactical sugar on top of Promise. If you end up with a Promise at the end, you still need to treat it like a Promise.

const response = f().then(() => { });

Or, if you are calling it inside of an async function, you can await to resolve it:

async function main() {
  const response = await f();
  console.log(response);
}

A pattern I like to use is have my main code wrapped in a self-executing async function, so I can still use await:

(async () => {
  const result = await doSomething();
  console.log(result);
})();

Note that even with that pattern, I need a final catch() to catch any errors it may have that aren't caught otherwise:

(async () => {
  // blah blah
})().catch(() => {});