Python - Find second smallest number

Question

I found this code on this site to find the second largest number:

def second_largest(numbers):
    m1, m2 = None, None
    for x in numbers:
        if x >         


        

Answer 1

I am writing the code which is using recursion to find the second smallest element in a list.

def small(l):
 small.counter+=1;
 min=l[0];

 emp=[]

 for i in range(len(l)):
    if l[i]

You can test it with various input integers.