Python - Find second smallest number

Question

I found this code on this site to find the second largest number:

def second_largest(numbers):
    m1, m2 = None, None
    for x in numbers:
        if x >         


        

Answer 1

Solution that returns second unique number in list with no sort:

def sec_smallest(numbers):
    smallest = float('+inf')
    small = float('+inf')
    for i in numbers:
        if i < smallest:
            small = smallest
            smallest = i
        elif i < small and i != smallest:
            small = i
    return small

print('Sec_smallest:', sec_smallest([1, 2, -8, -8, -2, 0]))