Passing a SQL parameter to an IN() clause using typed datasets in .NET

Question

First apologies as there are similar questions on this site, but none of them answer this problem directly.

Im using typed datasets in VS 2010. I create a TableAdapt

Answer 1

SQL Server 2008 has a feature called Table-Valued Parameters

So you need to

1. define your query as SELECT * from Table WHERE ID IN (SELECT * FROM (@IDs))
2. go back in the TableAdapter visual designer in Visual Studio, and update the @IDS parameter to modify the @IDS parameter as DbType=Object and ProviderType=Structured
3. run this SQL batch in the database your are using: CREATE TYPE MyIntArray AS TABLE ( Value INT );GO. This will create a MyIntArray "table type" with just one column of INT type.
4. Now the tricky thing is to pass the "MyIntArray" type to the TableAdapter, on the ADO.NET side.

Unfortunately the Table Adapter designer does not support the SqlParameter.TypeName argument, so we need to fix it by ourselves. The goal is to modify the CommandCollection property of the generated TableAdapter class. Unfortunately, this property is protected, so you have to derive the TableAdapter or for example use Reflection to tweak it. Here is an example with a derived class:

    public class MyTableAdapter2 : MyTableAdapter
    {
        public MyTableAdapter2()
        {
            SqlCommand[] cmds = base.CommandCollection;
            // here, the IDS parameter is index 0 of command 1
            // you'll have to be more clever, but you get the idea
            cmds[1].Parameters[0].TypeName = "MyIntArray";
        }
    }

And this is how you can call this method:

        MyTableAdapter t = new MyTableAdapter2();

        // create the TVP parameter, with one column. the name is irrelevant.
        DataTable tvp = new DataTable();
        tvp.Columns.Add();

        // add one row for each value
        DataRow row = tvp.NewRow();
        row[0] = 1;
        tvp.Rows.Add(row);

        row = tvp.NewRow();
        row[0] = 2;
        tvp.Rows.Add(row);

        row = tvp.NewRow();
        row[0] = 3;
        tvp.Rows.Add(row);

        t.Fill(new MyDataTable(), tvp);