An iterative algorithm for Fibonacci numbers

Question

I am interested in an iterative algorithm for Fibonacci numbers, so I found the formula on wiki...it looks straight forward so I tried it in Python...it doesn\'t have a prob

Answer 1

Non recursive Fibonacci sequence in python

def fibs(n):
    f = []
    a = 0
    b = 1
    if n == 0 or n == 1:
        print n
    else:
        f.append(a)
        f.append(b)
        while len(f) != n:
            temp = a + b
            f.append(temp)
            a = b
            b = temp

    print f

fibs(10)

Output: [0, 1, 1, 2, 3, 5, 8, 13, 21, 34]