How to round corners of UIImage with Hexagon mask

Question

I\'m trying to add a hexagon mask to a UIImage which I has been successful in. However I am unable to round the sides of the hexagon mask. I thought adding cell.profilePic.l

Answer 1

Here's a conversion of the roundedPolygon method for Swift.

func roundedPolygonPathWithRect(square: CGRect, lineWidth: Float, sides: Int, cornerRadius: Float) -> UIBezierPath {
    var path = UIBezierPath()

    let theta = Float(2.0 * M_PI) / Float(sides)
    let offset = cornerRadius * tanf(theta / 2.0)
    let squareWidth = Float(min(square.size.width, square.size.height))

    var length = squareWidth - lineWidth

    if sides % 4 != 0 {
        length = length * cosf(theta / 2.0) + offset / 2.0
    }

    var sideLength = length * tanf(theta / 2.0)

    var point = CGPointMake(CGFloat((squareWidth / 2.0) + (sideLength / 2.0) - offset), CGFloat(squareWidth - (squareWidth - length) / 2.0))
    var angle = Float(M_PI)
    path.moveToPoint(point)

    for var side = 0; side < sides; side++ {

        let x = Float(point.x) + (sideLength - offset * 2.0) * cosf(angle)
        let y = Float(point.y) + (sideLength - offset * 2.0) * sinf(angle)

        point = CGPointMake(CGFloat(x), CGFloat(y))
        path.addLineToPoint(point)

        let centerX = Float(point.x) + cornerRadius * cosf(angle + Float(M_PI_2))
        let centerY = Float(point.y) + cornerRadius * sinf(angle + Float(M_PI_2))

        var center = CGPointMake(CGFloat(centerX), CGFloat(centerY))

        let startAngle = CGFloat(angle) - CGFloat(M_PI_2)
        let endAngle = CGFloat(angle) + CGFloat(theta) - CGFloat(M_PI_2)

        path.addArcWithCenter(center, radius: CGFloat(cornerRadius), startAngle: startAngle, endAngle: endAngle, clockwise: true)

        point = path.currentPoint
        angle += theta
    }

    path.closePath()

    return path
}