Split function in oracle to comma separated values with automatic sequence

Question

Need Split function which will take two parameters, string to split and delimiter to split the string and return a table with columns Id and Data.And how to call Split funct

Answer 1

This function returns the nth part of input string MYSTRING. Second input parameter is separator ie., SEPARATOR_OF_SUBSTR and the third parameter is Nth Part which is required.

Note: MYSTRING should end with the separator.

create or replace FUNCTION PK_GET_NTH_PART(MYSTRING VARCHAR2,SEPARATOR_OF_SUBSTR VARCHAR2,NTH_PART NUMBER)
RETURN VARCHAR2
IS
NTH_SUBSTR VARCHAR2(500);
POS1 NUMBER(4);
POS2 NUMBER(4);
BEGIN
IF NTH_PART=1 THEN
SELECT REGEXP_INSTR(MYSTRING,SEPARATOR_OF_SUBSTR, 1, 1)  INTO POS1 FROM DUAL; 
SELECT SUBSTR(MYSTRING,0,POS1-1) INTO NTH_SUBSTR FROM DUAL;
ELSE
SELECT REGEXP_INSTR(MYSTRING,SEPARATOR_OF_SUBSTR, 1, NTH_PART-1) INTO  POS1 FROM DUAL; 
SELECT REGEXP_INSTR(MYSTRING,SEPARATOR_OF_SUBSTR, 1, NTH_PART)  INTO POS2 FROM DUAL; 
SELECT SUBSTR(MYSTRING,POS1+1,(POS2-POS1-1)) INTO NTH_SUBSTR FROM DUAL;
END IF;
RETURN NTH_SUBSTR;
END;

Hope this helps some body, you can use this function like this in a loop to get all the values separated:

SELECT REGEXP_COUNT(MYSTRING, '~', 1, 'i') INTO NO_OF_RECORDS FROM DUAL;
WHILE NO_OF_RECORDS>0
LOOP
    PK_RECORD    :=PK_GET_NTH_PART(MYSTRING,'~',NO_OF_RECORDS);
    -- do some thing
    NO_OF_RECORDS  :=NO_OF_RECORDS-1;
END LOOP;

Here NO_OF_RECORDS,PK_RECORD are temp variables.

Hope this helps.