comparing numpy arrays containing NaN

Question

For my unittest, I want to check if two arrays are identical. Reduced example:

a = np.array([1, 2, np.NaN])
b = np.array([1, 2, np.NaN])
if np.all(a==b):
          


        

Answer 1

When I used the above answer:

 ((a == b) | (numpy.isnan(a) & numpy.isnan(b))).all()

It gave me some erros when evaluate list of strings.

This is more type generic:

def EQUAL(a,b):
    return ((a == b) | ((a != a) & (b != b)))