Split a string by whitespace, keeping quoted segments, allowing escaped quotes

Question

I currently have this regular expression to split strings by all whitespace, unless it\'s in a quoted segment:

keywords = \'pop rock \"hard rock\"\';
keyword         


        

Answer 1

ES6 solution supporting:

• Split by space except for inside quotes
• Removing quotes but not for backslash escaped quotes
• Escaped quote become quote
• Can put quotes anywhere

Code:

keywords.match(/\\?.|^$/g).reduce((p, c) => {
        if(c === '"'){
            p.quote ^= 1;
        }else if(!p.quote && c === ' '){
            p.a.push('');
        }else{
            p.a[p.a.length-1] += c.replace(/\\(.)/,"$1");
        }
        return  p;
    }, {a: ['']}).a

Output:

[ 'pop', 'rock', 'hard rock', '"dream" pop' ]