How to deal with the URISyntaxException

Question

I got this error message :

java.net.URISyntaxException: Illegal character in query at index 31: http://finance.yahoo.com/q/h?s=^IXIC

Answer 1

Rather than encoding the URL beforehand you can do the following

String link = "http://example.com";
URL url = null;
URI uri = null;

try {
   url = new URL(link);
} catch(MalformedURLException e) {
   e.printStackTrace();
}

try{
   uri = new URI(url.toString())
} catch(URISyntaxException e {
   try {
        uri = new URI(url.getProtocol(), url.getUserInfo(), url.getHost(),
                      url.getPort(), url.getPath(), url.getQuery(), 
                      url.getRef());
   } catch(URISyntaxException e1 {
        e1.printStackTrace();
   }
}
try {
   url = uri.toURL()
} catch(MalfomedURLException e) {
   e.printStackTrace();
}

String encodedLink = url.toString();