Deserialize json in a “TryParse” way

Question

When I send a request to a service (that I do not own), it may respond either with the JSON data requested, or with an error that looks like this:

{
    \"er         


        

Answer 1

Just to provide an example of the try/catch approach (it may be useful to somebody).

public static bool TryParseJson(this string obj, out T result)
{
    try
    {
        // Validate missing fields of object
        JsonSerializerSettings settings = new JsonSerializerSettings();
        settings.MissingMemberHandling = MissingMemberHandling.Error;

        result = JsonConvert.DeserializeObject(obj, settings);
        return true;
    }
    catch (Exception)
    {
        result = default(T);
        return false;
    }
}

Then, it can be used like this:

var result = default(MyObject);
bool isValidObject = jsonString.TryParseJson(out result);

if(isValidObject)
{
    // Do something
}