Deserialize json in a “TryParse” way

Question

When I send a request to a service (that I do not own), it may respond either with the JSON data requested, or with an error that looks like this:

{
    \"er         


        

Answer 1

With Json.NET you can validate your json against a schema:

 string schemaJson = @"{
 'status': {'type': 'string'},
 'error': {'type': 'string'},
 'code': {'type': 'string'}
}";

JsonSchema schema = JsonSchema.Parse(schemaJson);

JObject jobj = JObject.Parse(yourJsonHere);
if (jobj.IsValid(schema))
{
    // Do stuff
}

And then use that inside a TryParse method.

public static T TryParseJson(this string json, string schema) where T : new()
{
    JsonSchema parsedSchema = JsonSchema.Parse(schema);
    JObject jObject = JObject.Parse(json);

    return jObject.IsValid(parsedSchema) ? 
        JsonConvert.DeserializeObject(json) : default(T);
}

Then do:

var myType = myJsonString.TryParseJson(schema);

Update:

Please note that schema validation is no longer part of the main Newtonsoft.Json package, you'll need to add the Newtonsoft.Json.Schema package.

Update 2:

As noted in the comments, "JSONSchema" have a pricing model, meaning it isn't free. You can find all the information here