How do I display a file's Properties dialog from C#?

Question

how to open an file\'s Properties dialog by a button

private void button_Click(object sender, EventArgs e)
{
    string path = @\"C:\\Users\\test\\Documents         


        

Answer 1

Call Process.Start, passing a ProcessStartInfo containing the name of the file, and with the ProcessStartInfo.Verb set to properties. (For more info, see the description of the unmanaged SHELLEXECUTEINFO structure, which is what ProcessStartInfo wraps, and in particular the lpVerb member.)