Get the nth item of a generator in Python

Question

Is there a more syntactically concise way of writing the following?

gen = (i for i in xrange(10))
index = 5
for i, v in enumerate(gen):
    if i is index:
           


        

Answer 1

Perhaps you should elaborate more on a actual use case.

>>> gen = xrange(10)
>>> ind=5 
>>> gen[ind]
5