Get the nth item of a generator in Python

Question

Is there a more syntactically concise way of writing the following?

gen = (i for i in xrange(10))
index = 5
for i, v in enumerate(gen):
    if i is index:
           


        

Answer 1

Best to use is : example :

a = gen values ('a','c','d','e')

so the answer will be :

a = list(a) -> this will convert the generator to a list (it will store in memory)

then when you want to go specific index you will :

a[INDEX] -> and you will able to get the value its holds 

if you want to know only the count or to do operations that not required store in memory best practice will be : a = sum(1 in i in a) -> this will count the number of objects you have

hope i made it more simple.