Can one partially apply the second argument of a function that takes no keyword arguments?

Question

Take for example the python built in pow() function.

xs = [1,2,3,4,5,6,7,8]

from functools import partial

list(map(partial(pow,2),xs))

>&g         


        

Answer 1

No

According to the documentation, partial cannot do this (emphasis my own):

partial.args

The leftmost positional arguments that will be prepended to the positional arguments

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You could always just "fix" pow to have keyword args:

_pow = pow
pow = lambda x, y: _pow(x, y)