How to extract group from regular expression in Oracle?

Question

I got this query and want to extract the value between the brackets.

select de_desc, regexp_substr(de_desc, \'\\[(.+)\\]\', 1)
from DATABASE
where col_name l         


        

Answer 1

You need to do a replace and use a regex pattern that matches the whole string.

select regexp_replace(de_desc, '.*\[(.+)\].*', '\1') from DATABASE;