How to determine file, function and line number?

Question

In C++, I can print debug output like this:

printf(
   \"FILE: %s, FUNC: %s, LINE: %d, LOG: %s\\n\",
   __FILE__,
   __FUNCTION__,
   __LINE__,
   logmessage         


        

Answer 1

There is a module named inspect which provides these information.

Example usage:

import inspect

def PrintFrame():
  callerframerecord = inspect.stack()[1]    # 0 represents this line
                                            # 1 represents line at caller
  frame = callerframerecord[0]
  info = inspect.getframeinfo(frame)
  print(info.filename)                      # __FILE__     -> Test.py
  print(info.function)                      # __FUNCTION__ -> Main
  print(info.lineno)                        # __LINE__     -> 13

def Main():
  PrintFrame()                              # for this line

Main()

However, please remember that there is an easier way to obtain the name of the currently executing file:

print(__file__)