Python: give start and end of week data from a given date

Question

day = \"13/Oct/2013\"
print(\"Parsing :\",day)
day, mon, yr= day.split(\"/\")
sday = yr+\" \"+day+\" \"+mon
myday = time.strptime(sday, \'%Y %d %b\')
Sstart = yr+\"          


        

Answer 1

Slight variation if you want to keep the standard time formatting and refer to the current day:

from datetime import datetime, timedelta

today = datetime.now().date()
start = today - timedelta(days=today.weekday())
end = start + timedelta(days=6)
print("Today: " + str(today))
print("Start: " + str(start))
print("End: " + str(end))