open-ended function arguments with TypeScript

Question

IMO, one of the main concerns of the TypeScript language is to support the existing vanilla JavaScript code. This is the impression I had at first glance. Take a look at the

Answer 1

In addition to @chuckj answer: You can also use an arrow function expression in TypeScript (is kind of a lambda in Java / .NET)

function sum(...nums: number[]): number {
    return nums.reduce((a, b) => a + b, 0);
}