Round float to x decimals?

Question

Is there a way to round a python float to x decimals? For example:

>>> x = roundfloat(66.66666666666, 4)
66.6667
>>>x = roundfloat(1.295782         


        

Answer 1

Use the built-in function round():

In [23]: round(66.66666666666,4)
Out[23]: 66.6667

In [24]: round(1.29578293,6)
Out[24]: 1.295783

help on round():

round(number[, ndigits]) -> floating point number

Round a number to a given precision in decimal digits (default 0 digits). This always returns a floating point number. Precision may be negative.