Default initialization of std::array?

Question

With C++11 std::array, do I have the guarantee that the syntax std::array x; will default-initialize all the elements of the array ?

Answer 1

Both T x[N]; and std::array x; default-initialize every element of the array.

For example, if T = std::string, every element will be an empty string. If T is a class without a default constructor, both will fail to compile. If T = int, every element will have indeterminate value (unless that declaration happens to be at namespace scope)