Select Pandas rows based on list index

Question

I have a dataframe df :

   20060930  10.103       NaN     10.103   7.981
   20061231  15.915       NaN     15.915  12.686
   20070331   3.196       NaN               


        

Answer 1

Another way (although it is a longer code) but it is faster than the above codes. Check it using %timeit function:

df[df.index.isin([1,3])]

PS: You figure out the reason