Calculate largest rectangle in a rotated rectangle

Question

I\'m trying to find the best way to calculate the biggest (in area) rectangle which can be contained inside a rotated rectangle.

Some pictures should help (I hope) i

Answer 1

@Andri is not working correctly for image where width > height as I tested. So, I fixed and optimized his code by such way (with only two trigonometric functions):

calculateLargestRect = function(angle, origWidth, origHeight) {
    var w0, h0;
    if (origWidth <= origHeight) {
        w0 = origWidth;
        h0 = origHeight;
    }
    else {
        w0 = origHeight;
        h0 = origWidth;
    }
    // Angle normalization in range [-PI..PI)
    var ang = angle - Math.floor((angle + Math.PI) / (2*Math.PI)) * 2*Math.PI; 
    ang = Math.abs(ang);      
    if (ang > Math.PI / 2)
        ang = Math.PI - ang;
    var sina = Math.sin(ang);
    var cosa = Math.cos(ang);
    var sinAcosA = sina * cosa;
    var w1 = w0 * cosa + h0 * sina;
    var h1 = w0 * sina + h0 * cosa;
    var c = h0 * sinAcosA / (2 * h0 * sinAcosA + w0);
    var x = w1 * c;
    var y = h1 * c;
    var w, h;
    if (origWidth <= origHeight) {
        w = w1 - 2 * x;
        h = h1 - 2 * y;
    }
    else {
        w = h1 - 2 * y;
        h = w1 - 2 * x;
    }
    return {
        w: w,
        h: h
    }
}

UPDATE

Also I decided to post the following function for proportional rectange calculating:

calculateLargestProportionalRect = function(angle, origWidth, origHeight) {
    var w0, h0;
    if (origWidth <= origHeight) {
        w0 = origWidth;
        h0 = origHeight;
    }
    else {
        w0 = origHeight;
        h0 = origWidth;
    }
    // Angle normalization in range [-PI..PI)
    var ang = angle - Math.floor((angle + Math.PI) / (2*Math.PI)) * 2*Math.PI; 
    ang = Math.abs(ang);      
    if (ang > Math.PI / 2)
        ang = Math.PI - ang;
    var c = w0 / (h0 * Math.sin(ang) + w0 * Math.cos(ang));
    var w, h;
    if (origWidth <= origHeight) {
        w = w0 * c;
        h = h0 * c;
    }
    else {
        w = h0 * c;
        h = w0 * c;
    }
    return {
        w: w,
        h: h
    }
}