Convert integer into its character equivalent, where 0 => a, 1 => b, etc

Question

I want to convert an integer into its character equivalent based on the alphabet. For example:

0 => a
1 => b
2 => c
3 => d

etc.

Answer 1

A simple answer would be (26 characters):

String.fromCharCode(97+n);

If space is precious you could do the following (20 characters):

(10+n).toString(36);

Think about what you could do with all those extra bytes!

How this works is you convert the number to base 36, so you have the following characters:

0123456789abcdefghijklmnopqrstuvwxyz
^         ^
n        n+10

By offsetting by 10 the characters start at a instead of 0.

Not entirely sure about how fast running the two different examples client-side would compare though.