Gulp.js task, return on src?

Question

I\'m new to gulp and have been looking through example set-ups. Some people have the following structure:

gulp.task(\"XXXX\", function() {
    gulp.src(\"...         


        

Answer 1

You return to indicate that the task is async. gulp.src() returns a stream, so it's async.

Without it the task system wouldn't know when it finished. Read the docs.