filename and line number of python script

Question

How can I get the file name and line number in python script.

Exactly the file information we get from an exception traceback. In this case without raising an excep

Answer 1

import inspect    

file_name = __FILE__
current_line_no = inspect.stack()[0][2]
current_function_name = inspect.stack()[0][3]

#Try printing inspect.stack() you can see current stack and pick whatever you want