filename and line number of python script

Question

How can I get the file name and line number in python script.

Exactly the file information we get from an exception traceback. In this case without raising an excep

Answer 1

Just to contribute,

there is a linecache module in python, here is two links that can help.

linecache module documentation
linecache source code

In a sense, you can "dump" a whole file into its cache , and read it with linecache.cache data from class.

import linecache as allLines
## have in mind that fileName in linecache behaves as any other open statement, you will need a path to a file if file is not in the same directory as script
linesList = allLines.updatechache( fileName ,None)
for i,x in enumerate(lineslist): print(i,x) #prints the line number and content
#or for more info
print(line.cache)
#or you need a specific line
specLine = allLines.getline(fileName,numbOfLine)
#returns a textual line from that number of line

For additional info, for error handling, you can simply use

from sys import exc_info
try:
     raise YourError # or some other error
except Exception:
     print(exc_info() )