filename and line number of python script

Question

How can I get the file name and line number in python script.

Exactly the file information we get from an exception traceback. In this case without raising an excep

Answer 1

Handy if used in a common file - prints file name, line number and function of the caller:

import inspect
def getLineInfo():
    print(inspect.stack()[1][1],":",inspect.stack()[1][2],":",
          inspect.stack()[1][3])