Error handling in getJSON calls

Question

How can you handle errors in a getJSON call? Im trying to reference a cross-domain script service using jsonp, how do you register an error method?

Answer 1

Here's my addition.

From http://www.learnjavascript.co.uk/jq/reference/ajax/getjson.html and the official source

"The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callback methods introduced in jQuery 1.5 are deprecated as of jQuery 1.8. To prepare your code for their eventual removal, use jqXHR.done(), jqXHR.fail(), and jqXHR.always() instead."

I did that and here is Luciano's updated code snippet:

$.getJSON("example.json", function() {
  alert("success");
})
.done(function() { alert('getJSON request succeeded!'); })
.fail(function() { alert('getJSON request failed! '); })
.always(function() { alert('getJSON request ended!'); });

And with error description plus showing all json data as a string:

$.getJSON("example.json", function(data) {
  alert(JSON.stringify(data));
})
.done(function() { alert('getJSON request succeeded!'); })
.fail(function(jqXHR, textStatus, errorThrown) { alert('getJSON request failed! ' + textStatus); })
.always(function() { alert('getJSON request ended!'); });

If you don't like alerts, substitute them with console.log

$.getJSON("example.json", function(data) {
  console.log(JSON.stringify(data));
})
.done(function() { console.log('getJSON request succeeded!'); })
.fail(function(jqXHR, textStatus, errorThrown) { console.log('getJSON request failed! ' + textStatus); })
.always(function() { console.log('getJSON request ended!'); });