How define an array of function pointers in C

Question

I\'ve a little question. I\'m trying to define an array of function pointers dynamically with calloc. But I don\'t know how to write the syntax. Thanks a lot.<

Answer 1

You'd declare an array of function pointers as

T (*afp[N])(); 

for some type T. Since you're dynamically allocating the array, you'd do something like

T (**pfp)() = calloc(num_elements, sizeof *pfp);

or

T (**pfp)() = malloc(num_elements * sizeof *pfp);

You'd then call each function as

T x = (*pfp[i])();

or

T x = pfp[i](); // pfp[i] is implicitly dereferenced

If you want to be unorthodox, you can declare a pointer to an array of pointers to functions, and then allocate that as follows:

T (*(*pafp)[N])() = malloc(sizeof *pafp);

although you would have to deference the array pointer when making the call:

x = (*(*pafp)[i])();