I have a (somewhat?) basic question regarding time conversions in Swift.
I have an integer that I would like converted into Hours / Minutes / Second
Here is a more structured/flexible approach: (Swift 3)
struct StopWatch {
var totalSeconds: Int
var years: Int {
return totalSeconds / 31536000
}
var days: Int {
return (totalSeconds % 31536000) / 86400
}
var hours: Int {
return (totalSeconds % 86400) / 3600
}
var minutes: Int {
return (totalSeconds % 3600) / 60
}
var seconds: Int {
return totalSeconds % 60
}
//simplified to what OP wanted
var hoursMinutesAndSeconds: (hours: Int, minutes: Int, seconds: Int) {
return (hours, minutes, seconds)
}
}
let watch = StopWatch(totalSeconds: 27005 + 31536000 + 86400)
print(watch.years) // Prints 1
print(watch.days) // Prints 1
print(watch.hours) // Prints 7
print(watch.minutes) // Prints 30
print(watch.seconds) // Prints 5
print(watch.hoursMinutesAndSeconds) // Prints (7, 30, 5)
Having an approach like this allows the adding of convenience parsing like this:
extension StopWatch {
var simpleTimeString: String {
let hoursText = timeText(from: hours)
let minutesText = timeText(from: minutes)
let secondsText = timeText(from: seconds)
return "\(hoursText):\(minutesText):\(secondsText)"
}
private func timeText(from number: Int) -> String {
return number < 10 ? "0\(number)" : "\(number)"
}
}
print(watch.simpleTimeString) // Prints 07:30:05
It should be noted that purely Integer based approaches don't take leap day/seconds into account. If the use case is dealing with real dates/times Date and Calendar should be used.