Count number of 1's in binary representation

Question

Efficient way to count number of 1s in the binary representation of a number in O(1) if you have enough memory to play with. This is an interview question I found on an onli

Answer 1

Ruby implementation

def find_consecutive_1(n)
  num = n.to_s(2)
  arr = num.split("")
  counter = 0
  max = 0
  arr.each do |x|
      if x.to_i==1
          counter +=1
      else
          max = counter if counter > max
          counter = 0 
      end
      max = counter if counter > max  
  end
  max
end

puts find_consecutive_1(439)