Count number of 1's in binary representation

Question

Efficient way to count number of 1s in the binary representation of a number in O(1) if you have enough memory to play with. This is an interview question I found on an onli

Answer 1

public static void main(String[] args) {

    int a = 3;
    int orig = a;
    int count = 0;
    while(a>0)
    {
        a = a >> 1 << 1;
        if(orig-a==1)
            count++;
        orig = a >> 1;
        a = orig;
    }

    System.out.println("Number of 1s are: "+count);
}