Can lambda functions be templated?

Question

In C++11, is there a way to template a lambda function? Or is it inherently too specific to be templated?

I understand that I can define a classic templated class/fu

Answer 1

In C++11, lambda functions can not be templated, but in the next version of the ISO C++ Standard (often called C++14), this feature will be introduced. [Source]

Usage example:

auto get_container_size = [] (auto container) { return container.size(); };

Note that though the syntax uses the keyword auto, the type deduction will not use the rules of auto type deduction, but instead use the rules of template argument deduction. Also see the proposal for generic lambda expressions(and the update to this).